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The angular velocity and the amplitude of a simple pendulum are omega and a, respectively. The ratio of its kinetic and potential energies at a displacement x from the mean position is…………… |
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Answer» `(X^(2)omega^(2))/(a^(2)-x^(2)omega^(2))` Potential energy `U=(1)/(2)momega^(2)x^(2)implies(K)/(U)=(a^(2)-x^(2))/(x^(2))` |
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