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The angles of a Quadrilateral are in A.P. and the greatest angle is double the least . Find angles of the quadrilateral in radian |
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Answer» Answer: LET the angles be (a−3d) 0 ,(a−d) 0 ,(a+d) 0 ,(a+3d) 0 being the common difference of the A.P. Therefore, sum of all the angles of a quadrilateral is ALWAYS 360 0 . (a−3d) 0 +(a−d) 0 +(a+d) 0 +(a+3d) 0 =360 0
4a=360 0
a=90 0 .....(i) It is GIVEN that the greatest angle is twice of the least Therefore, a+3d=2(a−3d) ⇒a=9d Substituting the value of a from (i) 90 0 =9d d=10 0
Hence the least angle is (a−3d) 0 =90 0 −30 0 =60 0 = 3 π
Step-by-step explanation: HOPE it will help you |
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