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The angles of a quadratrical in A.P with D=10° find the all angles of quadratrical |
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Answer» Let the angles of the quadriletarel be a°, (a+d)°, (a+2d)°, (a+3d)° Now, a°+(a+d)°+(a+2d)°+(a+3d)° = 360° =>4a°+(1+2+3)d° = 360° =>4a°+6d° = 360° =>4a+(6×10)° = 360° =>4a+60° = 360° =>4a = 300° =>a = 75° The angles are 75°, 85°, 95°, 105° Mark my ANSWER as BrainliestMark my answer as BrainliestFollow me if I was HELPFUL, you can ASK me your math QUERIES without any hesitation :) |
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