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The angles between the two vectors `vecA=3hati+4hatj+5hatk` and `vecB=3hati+4hatj-5hatk` will beA. zeroB. `180^(@)`C. `90^(@)`D. `45^(@)` |
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Answer» Correct Answer - 3 `cos theta = (vecA*vecB)/(AB) = ((3hati+4hatj+5hatk)*(3hati+4hatj-5hatk))/((5sqrt2)(5sqrt2))=0` `rArr theta = 90^(@)` |
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