1.

The angle of elevation of the top of a tower from a point on the ground Which is 30m away from the tower is 30°. find the height of tower​

Answer»

ong>Answer:

HEIGHT of the TOWER is 17.32 m.

Step-by-step explanation:

Given:

∅ = 30°

distance of tower from the point = 30m

i.e. adjacent side here

To find:

the height of the tower

we use TAN∅ = opposite/adjacent

we need to find the side opposite to ∅ =30°

let the opposite be x.

Solution:

tan∅ = tan 30° = 1/√3

\frac{1}{ \sqrt{3} } = \frac{x}{30} \\ x = \frac{30}{ \sqrt{3} } \\ = \frac{30 \times \sqrt{3} }{ \sqrt{3} \times \sqrt{3} } \\ = \frac{30 \times \sqrt{3} }{3} \\ = <klux>10</klux> \times \sqrt{3} \\ = 10 \sqrt{3} m

= 10(1.732). …(√3 = 1.732)

= 17.32 m

Thus, the height of tower is 17.32 m.


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