1.

the angle of elevation of the top of a tower from certain point is 30°.if the observer moves 20m towards the tower, the angle of elevation of the top increases 60°. find the height of the tower.​

Answer»

REFER to the ATTACHMENT for DIAGRAM

In Δ ABD ,

\implies  \tt \tan(30)  =  \frac{h}{x}

\implies \tt  \frac{1}{ \sqrt{3} }  =  \frac{h}{x}

\implies \tt x =  \sqrt{3} h

Now , in Δ ACD

\implies  \tt \tan(60) =  \frac{h}{x - 20}

\implies   \tt \sqrt{3}  =  \frac{h}{x - 20}

\implies   \tt \sqrt{3}  =  \frac{h}{( \sqrt{3}h - 20) }

\implies  \tt 3h - 20 \sqrt{3}  = h

\implies  \tt 2h = 20 \sqrt{3}

\implies \tt h = 10 \sqrt{3} \:  m

The height of tower is 10√3 meter



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