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The angle of elevation of the top of a hill at the foot of a tower is 60° and the angle ofdepression from the top of tower to the foot of hill is 30°. If tower is 50 metre high,find the height of the hill |
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Answer» ln ∆ABC, h/x = tan 60° ⇒ h = x√3 ln ∆BCD, 50/x = tan 30° ⇒ x = 50√3 ∴ h = 150 ∴ Height of hill = 150 m |
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