1.

The angle of elevation of the top of a hill at the foot of a tower is 60° and the angle ofdepression from the top of tower to the foot of hill is 30°. If tower is 50 metre high,find the height of the hill

Answer»

ln ∆ABC,

h/x = tan 60°

⇒ h = x√3

ln ∆BCD,

50/x = tan 30°

⇒ x = 50√3

∴ h = 150

∴ Height of hill = 150 m



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