1.

The angle of elevation of the top of a hill at the foot of a tower is 60° and the angle ofdepression from the top of tower to the foot of hill is 30°. If tower is 50 metre high,find the height of the hill.ORtanding oste to each other on either side of the

Answer»

Let AB is the Tower of height = h = 50 m.And, let the Height of Hill CD = H m.Distance between The root of the tower and hill = BCNow,In ΔABC∠C = 30° TAN(C) = AB/BC⇒ TAN(30) = 50/BC⇒ 1/√3 = 50 /BC⇒ BC = 50√3 m.Now,InΔBCD,∠B = 60° Tan(B) = CD/BC⇒ Tan(60) = H/BC⇒ BC√3 = H⇒ H = 50√3*√3 = 150 m.



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