The angle of contact of mercury with soda lime glass is 140^(@). A capillary tube of radius 1.0 mm is dipped in a trough containing mercury. By what amount does the mercury dip down in the tube relative to the liquid surface outside?Surface tension of mercury =0.465Nm^(-1) Density of mercury =13.6xx10^(3)kgm^(-3)

The angle of contact of mercury with soda lime glass is 140^(@). A cap

1.	The angle of contact of mercury with soda lime glass is 140^(@). A capillary tube of radius 1.0 mm is dipped in a trough containing mercury. By what amount does the mercury dip down in the tube relative to the liquid surface outside?Surface tension of mercury =0.465Nm^(-1) Density of mercury =13.6xx10^(3)kgm^(-3)
Answer» Solution :Capillary descent, `"" H = (2 T cos theta)/(R rho g) = (2 XX (0.465 Nm^(-1))(cos 140^@))/((2 xx 10^(-3) m)(13.6 xx 10^3)(9.8 m s^(-2)))` `implies "" h = -6.89 xx 10^(-4) m` Where, negative sign indicates that there is fall of mercury (mercury is DEPRESSED) in GLASS tube.