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The angle between two vectors given by `(6hati+6hatk)` and `(7hati+4hatj+4hatk)` is:A. `cos ^(-1)((1)/sqrt(3))`B. `cos^(-1)((5)/sqrt(3))`C. `sin^(-1)((2)/sqrt(3))`D. `sin^(-1)((sqrt(5))/(3))` |
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Answer» Correct Answer - D `cos theta=(vecB.vecB)/(AB)=((6hati+6hatj-3hatk).(7hati+4hatj+4hatk))/((sqrt(6^(2)+6^(2)+3^(2)))(sqrt(7^(2)+4^(2)+4^(2))))` `cos theta-(54)/(81)=(6)/(9)=(2)/(3)` `sin theta=sqrt(1-cos^(2)theta)=sqrt(5)/(3)` |
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