1.

the angle between the vectors (hati+hatj) and (hatj+hatk) is

Answer»

`30^(@)`
`45^(@)`
`60^(@)`
`90^(@)`

Solution :`cos theta =(VECA * vecB)/(|vecA||vecB|)`
`=((hati+hatj)*(hatj+hatk))/(SQRT(1+1)+sqrt(1+1))=(0+1+0)/(2)`
`cos theta = (1)/(2) cos 60^(@)`
`theta=60^(@)`


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