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The angle between the two vectors `vecA=3hati+4hatj+5hatk` and `vecB=3hati+4hatj-5hatk` will be :A. zeroB. `180^(@)`C. `90^(@)`D. `45^(@)` |
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Answer» Correct Answer - C `cos theta=(vecA.vecB)/(AB)=((3hati+4hatj)+5hatk)((3hati+4hatj-5hatk))/((5sqrt(2))(5sqrt(2)))=0` |
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