The angels of a triangle are (2x). (3x+5) and (4x-14) find x and measu

1.	The angels of a triangle are (2x). (3x+5) and (4x-14) find x and measure of angle
Answer» $\huge\fbox\red{\fbox\orange{Solution:-}}$ $\fbox\red{\fbox\orange{Given:-}}$ $\green{Angles\: are:-}$ $\pink{(2x)° \: (3x + 5)° \: (4x - 14)°}$ $\fbox\red{\fbox\orange{Formula}}$ $\red{sum \: of \:all \: angles \: of \: a \: triangle \: = 180°}$ $\fbox\red{\fbox\orange{By \: \: the \: problem:-}}$ $\blue{(2x) + (3x + 5)+ (4x - 14) = 180} \\ = > \orange{2x + 3x + 5 + 4x - 14 = 180} \\ = > \green{ 9x - 9 = 180} \\ = > \orange{9x = 180 + 9} \\ = > \pink{9x = 189} \\ = > \green{x = \frac{189}{9} } \\ = > \blue{x = 21°}$ $\fbox\red{\fbox\orange{Answer }}$ $\orange{1st \: angle = (21 \times 2) = 42°} \\ \green{ 2nd \: ange = (21 \times 3 )+ 5 = 68°} \\ \pink{3rd \: angle =( 21 \times 4) - 14 = 70°}$ $\blue{It \: can \: help \: you.}$

The angels of a triangle are (2x). (3x+5) and (4x-14) find x and measure of angle

Answer»

$\huge\fbox\red{\fbox\orange{Solution:-}}$

$\fbox\red{\fbox\orange{Given:-}}$

$\green{Angles\: are:-}$

$\pink{(2x)° \: (3x + 5)° \: (4x - 14)°}$

$\fbox\red{\fbox\orange{Formula}}$

$\red{sum \: of \:all \: angles \: of \: a \: triangle \: = 180°}$

$\fbox\red{\fbox\orange{By \: \: the \: problem:-}}$

$\blue{(2x) + (3x + 5)+ (4x - 14) = 180} \\ = > \orange{2x + 3x + 5 + 4x - 14 = 180} \\ = > \green{ 9x - 9 = 180} \\ = > \orange{9x = 180 + 9} \\ = > \pink{9x = 189} \\ = > \green{x = \frac{189}{9} } \\ = > \blue{x = 21°}$