Saved Bookmarks
| 1. |
The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B_(0)=510 nT. What is the amplitude of the electric field part of the wave ? |
|
Answer» SOLUTION :`B_(0)=510 nT =510xx10^(-9)T` `E_(0)=?` `c=(E_(0))/(B_(0)), E_(0)=c, B_(0)=3xx10^(8)xx510xx10^(-9)=153 NC^(-1)`. |
|