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The amount of (NH2)4SO4 in g, which must be added to 500 mL of 0.2 M NH3 to yield a solution of pH=9.35., if Kb for NH3=1.6×10−5 will be:( Give your answer upto two decimal only.)(Given, log1.6=0.2,log70=1.85) |
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Answer» The amount of (NH2)4SO4 in g, which must be added to 500 mL of 0.2 M NH3 to yield a solution of pH=9.35., if Kb for NH3=1.6×10−5 will be:( Give your answer upto two decimal only.) (Given, log1.6=0.2,log70=1.85) |
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