1.

The amount of heat evolved when 500 cm^(3) of 0.1 M HCl is mixed with 200 cm^(3) of 0.2 M NaOH is ……….

Answer»

2.292 kJ
1.292 kJ
0.292 kJ
3.392 kJ

Solution :`underset(underset(0.1 M)(500 cm^(3)))(HCl) + underset(underset(0.2 M)(200 cm^(3)))NaOH rarr NACL + H_(2)O`
Moles of HCl `= (0.1)/(1000) XX 500 = 0.05 moles`
Moles of NaOH `= (0.2)/(1000) xx 200 = 0.04 moles`
Moles of `H_(2)O` formed = 0.04 moles.
Heat released when 1 MOL `H_(2)O` is formed = 57.3 kJ
Heat released when 0.04 mol `H_(2)O` is fromed
`= 0.04 xx 57.3 = 2.292 kJ`


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