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| 1. |
The amount of calcium oxide required to react completely with 852 g of P_4O_{10} is : ( Atomic mass of P = 31) ( CaO + P_4O_{10} → Ca_3(PO)_4 ) |
| Answer» The amount of calcium oxide required to react completely with 852 g of P_4O_{10} is : ( Atomic mass of P = 31) ( CaO + P_4O_{10} → Ca_3(PO)_4 ) | |