1.

The amount of air present in a cylinder when a vacuum pump removes 1/4 of the air remaining in the cylinder at a time.​

Answer»

ANSWER:

no

it is not an arithmetic progression

Step-by-step explanation:

LET a be the amount of air INITIALLY Amount of air remaining after 1st pump =a –(a/4)=3a/4

Amount of air remaining after 2nd  pump= (3a/4) – (1/4)(3a/4)=9a/16

Amount of air remaining after 3RD  pump= (9a/16) – (1/4)(9a/16)=27a/64

So the series is like

a,3a/4,9a/4,27a/64……..

Difference Ist and second term=-a/4

Difference between Second and Third term= -3a/16

So difference is not constant

So it is not Arithmetic Progression

I think this answer is help ful;.


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