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The ages of three men are in the ratio 3:4:5. If the difference between the ages of the oldest and youngest is 18 years, find the sum of the ages of the three men. |
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Answer» Let the ages be 3x, 4X and 5X years. 5x - 3x = 18 2x = 18 x = 9 5x + 4x + 3x 12x 12 × 9 108 The sum of their ages is 108 years. |
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