1.

The ages of three men are in the ratio 3:4:5. If the difference between the ages of the oldest and youngest is 18 years, find the sum of the ages of the three men.

Answer»

Let the ages be 3x, 4X and 5X years.

5x - 3x = 18

2x = 18

x = 9

5x + 4x + 3x

12x

12 × 9

108

The sum of their ages is 108 years.



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