1.

The age of a father is 5 years mire than the age of 6 times of his son's age. After 7 years the age of father will be 3 more than his son's age. Find their present ages.

Answer»

LET AGE of son=x years
Age of father =6x+5 years
7 years later
Age of son=x+7 years
Age of father=3(x+7)
ATQ. 3(x+7)=6x+5+7
3x+21=6x+5+7
3x-6x=5+7-21
-3x=-9
3x=9
x=9/3=3
Age of son=x=3
Age of father=6x+5
6*3+5=23



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