The addition of HI in the presence of peroxide does not show anti-Mark – InterviewSolution

1.	The addition of HI in the presence of peroxide does not show anti-Markovnikov behavior because
Answer» the HI band is too strong not to be broken homolytically HI is reducing agent I free radical so formed readily combine with each other to give `I_(2)` MOLECULE I comine with H to give back HI Solution :H-I bond is WEAK (71/Kcal/mole) BREAKS homolytcically 1 free radical, it so formed combine each other PRODUCES `I_(2)` molecule.

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