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The acidic aqueous solution of ferrous ion forms a brown complex in the presence of `NO_(3)^(Θ)` by the follwing two steps: `[Fe(H_(2)O)_(6)]^(2+) +NO_(3)^(Θ) + H^(o+) rarr … + [Fe(H_(2)O)_(6)]^(3+) + H_(2)O` `[Fe(H_(2)O)_(6)]^(2+) +…rarr… + H_(2)O` Complete and balance the equations . |
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Answer» Correct Answer - `3[Fe(H_(2)O)_(6)]^(2+)+NO_(3)^(-) +H^(+) to NO +3[Fe(H_(2)O)_(6)]^(3+)` `[Fe(H_(2)O)_(6)]^(2+) + NO to [Fe(H_(2)O)_(5)]^(2+)+H_(2)O` |
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