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The accepted value for the density of gold metal is 19.31 g/cm^3. If a student measured the mass and volume of a sample of gold, and obtained a value of 19.03 g/cm^3, the percent difference would be ______(a) -1.5%(b) 1.5%(c) -0.5%(d) 0.5% |
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Answer» Correct answer is (a) -1.5% To elaborate: % difference = [(19.03 – 19.31) g/19.31 g] x 100% = – 1.5% A percent difference can be positive or negative; the sign shows whether the experimental value is higher or lower than the actual or theoretical value. This distinction is not used in precision since all values are experimental. |
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