1.

The acceleration due to gravity near the surface of a planet of radius R and density d is proportional to

Answer»

`d//R^(2)`
`dR^(2)`
dR
`d//R`

Solution :`g=(GM)/(R^(2))=G("volume"XX"DENSITY")/(R^(2))`
`=G.(4)/(3)(PIR^(3).d)/(R^(2))=(4 piG)/(3).d.R" or "g prop dR`


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