The ABC is a triangular plate of uniform thickness. The sides are in the ratio shown in the figure. I_(AB) , I_(BC) and l_(CA) are the moments of inertia of the plate about AB, BC and CA respectively. Which one of the following relation is correct?

The ABC is a triangular plate of uniform thickness. The sides are in t

1.	The ABC is a triangular plate of uniform thickness. The sides are in the ratio shown in the figure. I_(AB) , I_(BC) and l_(CA) are the moments of inertia of the plate about AB, BC and CA respectively. Which one of the following relation is correct?
Answer» `I_(AB)+I_(BC)=I_(CA)` `I_(CA)` is maximum `I_(AB)gtI_(BC)` `I_(BC)gtI_(AB)` Solution :The intersection of MEDIANS is the centre of mass of the triangle. Since the distances of centre of mass from the sides is RELATED as `x_(BC)gt x_(AB) gt x_(AC)`· Therefore `I_(BC)gtI_(AB)gtI_(AC)` or `I_(BC)gtI_(AB)`

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The ABC is a triangular plate of uniform thickness. The sides are in the ratio shown in the figure. I_(AB) , I_(BC) and l_(CA) are the moments of inertia of the plate about AB, BC and CA respectively. Which one of the following relation is correct?

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