The 9th term of an AP is equal to 7times , the 2nd term and 12th term

1.	The 9th term of an AP is equal to 7times , the 2nd term and 12th term exceeds 5times, the 3rd by two. Find the 1st term and the comman difference.
Answer» Answer: nth TERM = a+(n-1)d 9th term = 7(2nd term) a+(9-1)d = 7[a+(2-1)d] a+8d = 7a+7d d = 8a 12th term -5(3RD term) = 2 a+(12-1)d - 5[a+(3-1)d] = 2 a+11d - 5(a+2d) = 2 a+11d - 5a-10d = 2 -4a -d = 2 -4a -(8a) = 2 -12a = 2 a = -1/6 d = 8a = 8 × -1/6 = -4/3

The 9th term of an AP is equal to 7times , the 2nd term and 12th term exceeds 5times, the 3rd by two. Find the 1st term and the comman difference.

Answer»

Answer:

nth TERM = a+(n-1)d

9th term = 7(2nd term)

a+(9-1)d = 7[a+(2-1)d]

a+8d = 7a+7d

d = 8a

12th term -5(3RD term) = 2

a+(12-1)d - 5[a+(3-1)d] = 2

a+11d - 5(a+2d) = 2

a+11d - 5a-10d = 2

-4a -d = 2

-4a -(8a) = 2

-12a = 2

a = -1/6

d = 8a = 8 × -1/6 = -4/3

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The 9th term of an AP is equal to 7times , the 2nd term and 12th term exceeds 5times, the 3rd by two. Find the 1st term and the comman difference.​

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The 9th term of an AP is equal to 7times , the 2nd term and 12th term exceeds 5times, the 3rd by two. Find the 1st term and the comman difference.