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The 8/9th term of A.P is zero prove that its 29th term is divisible its 19th term |
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Answer» LET first term be a,common difference be d. Given.9th term is zero. therefore , a + (9 - 1)d =0 ,--> a + 8d =0 ....(1) 19th term = T19= a + (19 -1)d =a + 18d = -8d + 18d =10d ( a = -8d from EQN. (1) ). Similarly, T29 =a + (29 -1 )d= a + 28d = = -8d +28d =20d therefore, T19 = 10d and T29 = 20d Here we can simply SEE that T29 = 2 times of T19, 29TH term is DIVISIBLE by 19th term. |
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