1.

The 7th term of an A.P is 32 and its 13th term is 62. Find A.P

Answer»

t7 = 32, t13 = 62

a +cd = 32 ........ (1)

a +12d = 62 ......... (2)

Subtracting (2) from (1) -6d = -30 ⇒ d = 5

Then A.P is 2, 7, 12, 17 . . . 

Note:

OD ⊥ BD



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