Saved Bookmarks
| 1. |
The 7th term of an A.P is 32 and its 13th term is 62. Find A.P |
|
Answer» t7 = 32, t13 = 62 a +cd = 32 ........ (1) a +12d = 62 ......... (2) Subtracting (2) from (1) -6d = -30 ⇒ d = 5 Then A.P is 2, 7, 12, 17 . . . Note: OD ⊥ BD |
|