1.

The 7th and 13th terms of an AP be 34 and 64 then its 18th term is

Answer»

Answer:8

Step-by-step explanation:

Let 1st term be "a" and common difference be "d" then 7 term and 13 term can be WRITTEN as a+6d=34......EQU.(1) a+12d=64......equ.(2) Solve both equ. We get a=4 & d=5 then So, 18 term be a+17d= 4+17 5 = 899



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