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The 6th and 11th terms of an arithmetic sequence are 38 and 73.find the first term and write the algebric expression of the sequence |
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Answer» Step-by-step EXPLANATION: a6 = 38. a + 5d = 38 a = 38 - 5d.......equation 1 a11 = 73. a + 10d = 73 38 - 5d + 10d = 73........from equation 1 38 + 5d = 73 5d = 73 - 38 5d = 35 d = 35/5 d = 7 Put d = 7 in equation 1 a = 38 - 5 (7) a = 38 - 35 a = 3 Therefore ; the first term (a) = 3 a2 = a+d a3 = a +2d. A4 = a + 3d = 3+7 = 3 + 2(7). = 3 + 3(7) = 10. = 3 + 14. = 3 + 21 = 17. = 24 Therefore :the A.P. is 3, 10, 17, 24 |
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