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The 4th term of an AP is Zero. Prove that the 25th Term of the AP is 3 times its 11th Term |
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Answer» ONG>Step-by-step explanation: 4th term = a + 3D = 0 3d = 0 - a = 0 d = 0/3 = 0 so, a + 3(0) = 0 a + 0 = 0 a = 0 25th term = 3 × 11th term a + 24d = 3 × (a + 10d) 0 + 24(0) = 3 × [ 0 + 10(0) ] 0 + 0 = 3 × (0 + 0) 0 = 3 × 0 0 = 0 Hence Proved. Hope it helps u !!!!!!!!! |
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