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The 4th term of an Ap is zero .prove that its AP is 25 th term is tripple its 11th Term |
Answer» To PROVE :Proof :t(4) = a+3d = 0 ⇒a=-3d t(25) = a +24d = -3d +24d = 21d. t(11) = a + 10d = -3d + 10d = 7d therefore , t(25) = t(11) × 3 Hence proved !! |
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