The 17th term of an AP exceeds its 10th term by 7. Find the common dif

1.	The 17th term of an AP exceeds its 10th term by 7. Find the common difference.
Answer» Given A word problem To FIND Common DIFFERENCE =cd Solution *According to the question* 17th term = 10th term + 7 ( In an easy language) we have to find 17th and 10th term $\implies{T_n}=a+(n-1)d}$ Now $\implies{T_{10}}$ $\implies{T_{10}=a+(10-1)d}$ $\implies{T_{10}=a+(9)d}$ $\implies{T_{19}=a+9d}$ SIMILARLY $\implies{T_17}$ $\implies{T_{17}=a+(17-1)d}$ $\implies{T_{17}=a+16d}$ Putting the values =>a+16d=a+9d+7 =>16d-9d=7 =>7d=7 d=1 Hence,the VALUE of common difference be 1