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The 17 th term of an AP exceeds its 10th term by 7. Find the common difference, |
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Answer» Let a be the first term and d the common difference. It is given a_{17} - a_{10} = 7 (a + 16d) - (a + 9d) = 7 7d = 7 d = 1 Thus, the common difference is 7. a 17 - a 10 = 7; a + 16d = a + 9d ; 7 16d - 9d =7; 7d = 7, d = 7/7=1 |
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