1.

The 17 th term of an AP exceeds its 10th term by 7. Find the common difference,

Answer»

Let a be the first term and d the common difference.

It is given a_{17} - a_{10} = 7

(a + 16d) - (a + 9d) = 7

7d = 7 d = 1

Thus, the common difference is 7.

a 17 - a 10 = 7; a + 16d = a + 9d ; 7 16d - 9d =7; 7d = 7, d = 7/7=1



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