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. The 11th term and 31th term of an A.P are 25 and 65 respectively. Find the nth term of the AP |
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Answer» a(11) = a + 10d = 25 ....(1)a(31) = a + 30d = 65 .....(2)eq (2) - eq(1)40 = 20dd = 2a + 20 = 25a = 5a(n) = a + (n-1)d = 5 + (n-1)2 = 5 + 2n -2 = 2n+3 |
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