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The 10th term of the AP 1,3/2,2,5/2 ...... is *

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\large \orange{answer} \\ \\ \large \implies{t \: 10 = \frac{11}{2} } \\ \\ \large \implies{ \underline{given}} \\ \\ \large \implies{ap \: = \: 1 + \frac{3}{2} + 2 + \frac{5}{2} ...... \: n \: terms } \\ \\ \large \implies \underline{find \: \: 10 \: terms} \\ \\ \large \implies \underline{ solutions} \\ \\ \large \implies{first \: \: term \: \: a = 1} \\ \\ \large \implies{common \: \: difference \: \: d \: = \frac{3}{2} - 1 = \frac{1}{2} } \\ \\ \large \implies{t \: 10 \: terms \: = a + 9d} \\ \\ \large \implies{1 + 9 \times \frac{1}{2} } \\ \\ \large \implies \therefore{t \: 10 = \frac{11}{2} }


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