Ten years later, A will be twice as old as B and five years ago, A was

1.	Ten years later, A will be twice as old as B and five years ago, A was three times as old as B. What are the present ages of A and B?
Answer» Let the present ages of A and B be ‘a’ and ‘b’ respectively. Given, ten years later, A will be twice as old as B and five years ago, A was three times as old as B ⇒ a + 10 = 2(b + 10) ⇒ a = 2b + 10 ------- (1) Also, a – 5 = 3(b – 5) ⇒ a = 3b – 10 -------- (2) Equating eq2 and eq1 ⇒ 2b + 10 = 3b – 10 ⇒ b = 20 Thus, a = 2b + 10 = 50

Ten years later, A will be twice as old as B and five years ago, A was three times as old as B. What are the present ages of A and B?

Answer»

Let the present ages of A and B be ‘a’ and ‘b’ respectively.

Given, ten years later, A will be twice as old as B and five years ago,

A was three times as old as B

⇒ a + 10 = 2(b + 10)

⇒ a = 2b + 10 ------- (1)

Also,

a – 5 = 3(b – 5)

⇒ a = 3b – 10 -------- (2)

Equating eq2 and eq1

⇒ 2b + 10 = 3b – 10

⇒ b = 20

Thus,

a = 2b + 10 = 50