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Temperature of 100 g of water in a thermoflask remains fixed for a pretty long time at `50^(@)C`. An equal mass of sand at `20^(@)C` is poured in the flask and shaken for some time so that the temperature of the mixture is `40^(@)`. Now the experiment is repeated with 100g of a liquid at `50^(@) C` and an equal amount of sand at `20^(@)C` when the temperature of the mixture is found to be `30^(@)C` The specific heat of the liquid `(in KJ//KgxK)` isA. `1.05`B. `2.10`C. `4.20`D. `1.951` |
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Answer» Correct Answer - B `100 xx S_(w)xx10 =100xxS_(S)xx20` `100 xx S_(l) xx 20 = 100 xx S_(S) xx10` `S_(w),S_(l),S_(S)` are specific heat capacities of water liquid & sand respectively. `S_(l)=(S_(W))/(2)=2.10kJ..KgxxK`. |
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