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Answer»

First u have to FIND alpha+beta which means -b/a which is -(-4)/1 = 4.
Now find alpha X beta which means c/a which is 3/1 =3.
Now , alpha^4 x beta^4 + alpha^3 x beta^3 can be ALSO WRITTEN as
(alpha x beta)^4 + (alpha x beta)^3.
As we know that the SUM of two zeroes is 3 , now subtitute 3 in the place of alpha x beta.
U would be getting (3)^4 + (3)^3 = 108


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