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Tap A can fill a tank in 12 hrs while tap B can fill it in 15 hrs. If both the taps are opened together and after 3 hrs tap B is closed then in how much time will tap A take to fill the remaining tank |
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Answer» ong>Answer: Step-by-step explanation: Let us name the 3 Taps be T A ,T B ,T
where T B ,T C are EMPTYING pipes and T A is filling PIPE.
Water Emptied by T B in 6 hours=Volume of Tank or V Water Emptied by T B in 1 Hour= 6 V
Similarly, Water Emptied by T C in 8 Hour=V Water Emptied by T C in 1 Hour= 8 V
Similarly, Water Supplied by T A in 2 Hour=V Water Supplied by T A in 1 Hour= 2 V
After 2 Hours,
⇒2 2 V −2 8 V −2 6 V = 12 5V
After 3 Hours,
⇒ 12 5V + 2 V − 6 V = 4 3V
Now, only T A is opened
Remaining Volume=V− 4 3V = 4 V
Now Time taken to Fill Remaining Tank
⇒ 2 V
4 V
= 2 1 hrs=30min
Therefore Answer is (C) |
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