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tanx+tan2x+tanxtan2x=1 |
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Answer» tanx+tanw+tanxtan2x=1tanx+tan2x=1-tanxtan2xthanx+tan2x/1-tanx+tan2x=1Tan(2x+x)=π/4tan3x=tanπ/4now,3x=π/4x=nπ/3+π/12x=4π(n+1)/12 tanx+tan2x+tanxtan2x=1tanx+tan2x = 1 - tanxtan2x(tanx+tan2x)/(1 - tanxtan2x) = 1tan3x = 13x = π/4 + nπ, n = 0, ±1, ±2, ...x = π/12 + nπ/3= π/12(1 + 4n) |
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