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(tanx + cotx) dx. |
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Answer» ∫(tanx + cotx)²dx = ∫tan² x + 2tanx cot x + cot² x) dx = ∫(tan² x + cot² x + 2)dx = ∫(tan² x + 1 + cot² x + 1) dx = ∫(sec² x + cosec² x) dx = ∫(sec² x)dx + ∫(cosec² x)dx = tan x - cot x + C |
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