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Tanθ/1−cotθ+cotθ/1−tanθ=1+secθ⋅cosecθ |
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Answer» ============ ⭐⭐⭐⭐⭐⭐ ⭐ ⭐ ⭐ ⭐ ⭐ ❤❤❤⭐⭐⭐⭐ LHS = tanθ/(1 - cotθ) + cotθ/(1 - tanθ) = tanθ/(1 - 1/tanθ) + (1/tanθ)/(1 - tanθ) = tan²θ/(tanθ - 1) + 1/tanθ(1 - tanθ) = tan³θ/(tanθ - 1) - 1/tanθ(tanθ - 1) = (tan³θ - 1)/tanθ(tanθ - 1) = (tanθ - 1)(tan²θ + 1 + tanθ)/tanθ(tanθ - 1) = (tan²θ + 1 + tanθ)/tanθ = tanθ + cotθ + 1 = sinθ/cosθ + cosθ/sinθ + 1 = (sin²θ + cos²θ)/sinθ.cosθ + 1 = secθ.cosecθ + 1 = 1 + secθ.cosecθ = RHS ⤵⤵⤵⤵ FOLLOW , BRAINLIST ME☺☺PLZZ |
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