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Tano2 |
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Answer» To proof: tan²A - sin²A = tan² A sin²A from LHS, tan²A -sin²A = (sin²A / cos²A) - sin²A……[tan A=sin A/cos A] = (sin²A - sin²Acos²A) / cos²A = sin²A (1- cos²A) / cos² A [tan A = sinA / cos A] = tan²A sin²A= RHS .•. hence proved |
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