Saved Bookmarks
| 1. |
TanA=a\\a+1 tanB=1/2a+1 Find A+B |
| Answer» Tan(A+B) =tanA+tanB/(1-tanA.tanB) Tan(A+B) =a/(a+1)+1/(2a+1) ÷ 1-a/(a+1)(2a+1) Tan(A+B) = a(2a+1)+(a+1) / (a+1)(2a +1)-aTan(A+B)=1Tan(A+B)=Tan¶÷4A+B=¶÷4 | |