Tan32+tan13+tan32tan13=1

1.	Tan32+tan13+tan32tan13=1
Answer» tan 32o + tan 13o + tan 32o.tan13o = 1tan 32o + tan 13o = 1 - tan 32o.tan13o(tan 32o + tan 13o)/(1 - tan 32o.tan13o) = 1tan (32o + 13o) = 1 [Since tan (A + B) = (tan A + tan B)/(1 - tan A. tan B)]tan 45o = 11 = 1 [Since tan 45o = 1]Hence proved. Hello friends,If we can recall the formulatan( A+B)= ( tan A + tan B) /(1- tan A tan B)so let us takeA= 32 and B= 13therefore tan( 32+13) = (tan 32+ tan 13)/(1-tan32\xa0tan13)i.e tan 45 =\xa0(tan 32+ tan 13)/(1-tan32\xa0tan13) \xa0[since 32+13 =45]\xa01=\xa0(tan 32+ tan 13)/(1-tan32\xa0tan13) [tan 45 =1](1-tan32\xa0tan13) =\xa0(tan 32+ tan 13)1= tan32\xa0tan13\xa0+ tan 32+ tan 13PROOVEDThanksS Mukherjee7864927899\xa0

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