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Tan²theate +cot²theate |
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Answer» tan²Ө + cot²Ө = sin²Ө/cos²Ө + cos²Ө/sin²Ө → (sin⁴Ө + cos⁴Ө)/sin²Ө cos²Ө → (1 - 2sin²Ө cos²Ө)/sin²Ө cos²Ө {sin⁴x + cos⁴x = 1 - 2sinx cosx} → 4(1 - sin²2x)/sin²2x {sinx cosx = (SIN 2x)/2 , 2sinx cosx = sin 2x} → 4(cos²2x)/sin²2x {1 - sin²x = cos²x} → 4 cot²2x |
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