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Tan2 x – sin2x = tan2 x sin2 x |
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Answer» We have to prove that (tan x)^2 - (sin x)^2 = (tan x)^2 * (sin x)^2 Start from the LEFT HAND side: (tan x)^2 - (sin x)^2 use tan x = sin x / COS x (sin x)^2/(cos x)^2 - (sin x)^2 => [(sin x)^2 - (sin x)^2*(cos x)^2]/(cos x)^2 => (sin x)^2[1 - (cos x)^2]/(cos x)^2 => (sin x)^2 * [(sin x)^2 / (cos x)^2] => (tan x)^2 * (sin x)^2 which is the right hand side. This PROVES that (tan x)^2 - (sin x)^2 = (tan x)^2 * (sin x)^2 HOPE THIS HELPS PLZ MARK AS BRAINLIEST |
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