1.

tan1°+tan89°=A)1/sin1°B)2/sin2°C)2/sin1°D)1/sin2°E)1/2sin2°

Answer» tan1°+tan89°=
A)1/sin1°
B)2/sin2°
C)2/sin1°
D)1/sin2°
E)1/2sin2°


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