\tan \theta=\frac{4}{3} \frac{2 \sin \theta-3 \cos \theta}{2 \sin \th – InterviewSolution

1.	\tan \theta=\frac{4}{3} \frac{2 \sin \theta-3 \cos \theta}{2 \sin \theta+3 \cos \theta}=-\frac{1}{17}
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